What is the derivative of (80e^{-x/(10})-40x) ?

The derivative of (80e^{-x/(10})-40x) is -8e^{-x/(10)}-40

What is the first derivative of (80e^{-x/(10})-40x) ?

The first derivative of (80e^{-x/(10})-40x) is -8e^{-x/(10)}-40

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\frac{d}{d x} ((80 e^{- \frac{x}{10}}) - 40 x)

- 8 e^{- \frac{x}{10}} - 40

Solution steps

\frac{d}{d x} ((80 e^{- \frac{x}{10}}) - 40 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (80 e^{- \frac{x}{10}}) - \frac{d}{d x} (40 x)

\frac{d}{d x} (80 e^{- \frac{x}{10}}) = - 8 e^{- \frac{x}{10}}

\frac{d}{d x} (40 x) = 40

= - 8 e^{- \frac{x}{10}} - 40

x^{2} - 2 x, 3 x + 6

x \to 3 lim (- 3)

y = (\frac{x ^{2} + 2}{x ^{2} - 2})^{6}

\frac{\partial}{\partial x} (x ln (z^{3} + x^{6}))

y = tan (π - \frac{9}{x})

What is the derivative of (80e^{-x/(10})-40x) ?
The derivative of (80e^{-x/(10})-40x) is -8e^{-x/(10)}-40
What is the first derivative of (80e^{-x/(10})-40x) ?
The first derivative of (80e^{-x/(10})-40x) is -8e^{-x/(10)}-40