What is the derivative of 12+2.8sin((2pi)/(365)(t-80)) ?

The derivative of 12+2.8sin((2pi)/(365)(t-80)) is 0.04819…cos(0.01721…(t-80))

What is the first derivative of 12+2.8sin((2pi)/(365)(t-80)) ?

The first derivative of 12+2.8sin((2pi)/(365)(t-80)) is 0.04819…cos(0.01721…(t-80))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

12 + 2.8 sin (\frac{2 π}{365} (t - 80))

0.04819 \dots cos (0.01721 \dots (t - 80))

Solution steps

\frac{d}{d t} (12 + 2.8 sin (\frac{2 π}{365} (t - 80)))

Simplify

12 + 2.8 sin (\frac{2 π}{365} (t - 80)) : 12 + 2.8 sin (0.01721 \dots (t - 80))

= \frac{d}{d t} (12 + 2.8 sin (0.01721 \dots (t - 80)))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (12) + \frac{d}{d t} (2.8 sin (0.01721 \dots (t - 80)))

\frac{d}{d t} (12) = 0

\frac{d}{d t} (2.8 sin (0.01721 \dots (t - 80))) = 0.04819 \dots cos (0.01721 \dots (t - 80))

= 0 + 0.04819 \dots cos (0.01721 \dots (t - 80))

Simplify

= 0.04819 \dots cos (0.01721 \dots (t - 80))

n = 0 \sum \infty \frac{4}{2 ^{n}}

f (x) = cos (x)

(- 18 - 20) (- 18 - 15)

\int (\frac{x ^{6} - 5 x}{x ^{2}}) d x

x \to 0 lim (\frac{x}{sin ( \frac{x}{2} )})

What is the derivative of 12+2.8sin((2pi)/(365)(t-80)) ?
The derivative of 12+2.8sin((2pi)/(365)(t-80)) is 0.04819…cos(0.01721…(t-80))
What is the first derivative of 12+2.8sin((2pi)/(365)(t-80)) ?
The first derivative of 12+2.8sin((2pi)/(365)(t-80)) is 0.04819…cos(0.01721…(t-80))