What is the derivative of tan(2x+5) ?

The derivative of tan(2x+5) is sec^2(2x+5)*2

What is the first derivative of tan(2x+5) ?

The first derivative of tan(2x+5) is sec^2(2x+5)*2

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derivative of

tan (2 x + 5)

sec^{2} (2 x + 5) \cdot 2

Solution steps

\frac{d}{d x} (tan (2 x + 5))

Apply the chain rule:

sec^{2} (2 x + 5) \frac{d}{d x} (2 x + 5)

= sec^{2} (2 x + 5) \frac{d}{d x} (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

= sec^{2} (2 x + 5) \cdot 2

\int 2 + tan^{2} (x) d x

x \to \infty + lim (6 x)

7 x^{2} y^{^{''}} + 15 x y^{^{'}} + y = 48 x + 7

\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 6

\int sin (2 x) - 4 e^{3 x} d x

What is the derivative of tan(2x+5) ?
The derivative of tan(2x+5) is sec^2(2x+5)*2
What is the first derivative of tan(2x+5) ?
The first derivative of tan(2x+5) is sec^2(2x+5)*2