What is (\partial)/(\partial x)(e^xcos(y)-z) ?

The answer to (\partial)/(\partial x)(e^xcos(y)-z) is e^xcos(y)

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(\partial)/(\partial x)(e^xcos(y)-z)

\frac{\partial}{\partial x} (e^{x} cos (y) - z)

e^{x} cos (y)

Solution steps

\frac{\partial}{\partial x} (e^{x} cos (y) - z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x} cos (y)) - \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (e^{x} cos (y)) = cos (y) e^{x}

\frac{\partial}{\partial x} (z) = 0

= cos (y) e^{x} - 0

Simplify

= e^{x} cos (y)

\int \frac{x ^{3} + 1}{x ^{3} - x ^{2}} d x

\frac{d}{d y} (ln (y^{2}))

\int (\frac{x ^{3} + 7}{x ^{2}}) d x

\int_{- 3}^{0} ∣ x + 2 ∣ d x

\frac{d}{d x} (\frac{1}{arcsin ( x )})

What is (\partial)/(\partial x)(e^xcos(y)-z) ?
The answer to (\partial)/(\partial x)(e^xcos(y)-z) is e^xcos(y)