What is the limit as x approaches 0+of 2x^{sin(3x)} ?

The limit as x approaches 0+of 2x^{sin(3x)} is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 2x^{sin(3x)}

x \to 0 + lim (2 x^{s i n (3 x)})

2

Solution steps

x \to 0 + lim (2 x^{s i n (3 x)})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to 0 + lim (x^{s i n (3 x)})

Apply exponent rules

= 2 \cdot x \to 0 + lim (e^{s i n (3 x) l n (x)})

Apply the Limit Chain Rule:

1

= 2 \cdot 1

Simplify

= 2

\int x e^{5 x + π} d x

x \to - 8 lim (- \frac{3 x}{x + 8})

3 x^{3} 25 - x^{2}

\int_{6}^{8} \frac{70}{( x - 6 ) ^{3}} d x

1 - 3 x^{2}

What is the limit as x approaches 0+of 2x^{sin(3x)} ?
The limit as x approaches 0+of 2x^{sin(3x)} is 2