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Popular >

y^'=x(9-y)

Solution

y^{^{'}} = x (9 - y)

Solution

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 9

Solution steps

y^{'} (x) = x (9 - y)

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 9

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 9

Popular Examples

sum from n=1 to infinity of 1/(n+9)

n = 1 \sum \infty \frac{1}{n + 9}

integral of ((x-4)^2(x+1))/x

\int \frac{( x - 4 ) ^{2} ( x + 1 )}{x} d x

x y^{^{'}} = 2 y + 8 x

integral from 2 to 3 of (x^2+1)/(x^3+3x)

\int_{2}^{3} \frac{x ^{2} + 1}{x ^{3} + 3 x} d x

integral from 0 to 5 of x/(x-2)

\int_{0}^{5} \frac{x}{x - 2} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=x(9-y) ?
The solution for y^'=x(9-y) is y=-e^{-(x^2)/2-c_{1}}+9