What is the derivative of-cos(piy)dx ?

The derivative of-cos(piy)dx is pisin(piy)dx

What is the first derivative of-cos(piy)dx ?

The first derivative of-cos(piy)dx is pisin(piy)dx

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derivative of

- cos (π y) d x

π sin (π y) d x

Solution steps

\frac{d}{d y} (- cos (π y) d x)

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - d x \frac{d}{d y} (cos (π y))

Apply the chain rule:

- sin (π y) \frac{d}{d y} (π y)

= - sin (π y) \frac{d}{d y} (π y)

\frac{d}{d y} (π y) = π

= - d x (- sin (π y) π)

Simplify

= π sin (π y) d x

\int (3 x^{2} - 1) e^{x^{3} - x} d x

35 x ln (10 x)

(1 + x^{4}) d y + x (1 + 4 y^{2}) d x = 0, y (1) = 0

4 y^{^{''}} - y = 1

\int e^{3 x} d x

What is the derivative of-cos(piy)dx ?
The derivative of-cos(piy)dx is pisin(piy)dx
What is the first derivative of-cos(piy)dx ?
The first derivative of-cos(piy)dx is pisin(piy)dx