What is derivative of r=10^{2sqrt(t)} ?

The answer to derivative of r=10^{2sqrt(t)} is (dt)/(dr)=(sqrt(t))/(ln(10)*100^{sqrt(t))}

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derivative of r=10^{2sqrt(t)}

derivative of

r = 1 0^{2 t}

\frac{d t}{d r} = \frac{t}{ln ( 10 ) \cdot 10 0 ^{t}}

Solution steps

r = 1 0^{2 t}

Treat

t

t (r)

Differentiate both sides:

1 = \frac{ln ( 10 ) \cdot 10 0 ^{t} \frac{d t}{d r}}{t}

Isolate

\frac{d t}{d r} : \frac{d t}{d r} = \frac{t}{ln ( 10 ) \cdot 10 0 ^{t}}

\frac{d t}{d r} = \frac{t}{ln ( 10 ) \cdot 10 0 ^{t}}

\frac{\partial}{\partial x} (sin (π (4 x - 3 y)))

n = 1 \sum \infty \frac{( n )}{ln ( n )}

\frac{\partial}{\partial x} (x + y + ln (x y))

\int 1 - v d v

\int cot (1) d x

What is derivative of r=10^{2sqrt(t)} ?
The answer to derivative of r=10^{2sqrt(t)} is (dt)/(dr)=(sqrt(t))/(ln(10)*100^{sqrt(t))}