What is the derivative of sec(2ln(x)) ?

The derivative of sec(2ln(x)) is (2sec(2ln(x))tan(2ln(x)))/x

What is the first derivative of sec(2ln(x)) ?

The first derivative of sec(2ln(x)) is (2sec(2ln(x))tan(2ln(x)))/x

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\frac{d}{d x} (sec (2 ln (x)))

\frac{2 sec ( 2 ln ( x ) ) tan ( 2 ln ( x ) )}{x}

Solution steps

\frac{d}{d x} (sec (2 ln (x)))

Apply the chain rule:

sec (2 ln (x)) tan (2 ln (x)) \frac{d}{d x} (2 ln (x))

= sec (2 ln (x)) tan (2 ln (x)) \frac{d}{d x} (2 ln (x))

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

= sec (2 ln (x)) tan (2 ln (x)) \frac{2}{x}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 sec ( 2 ln ( x ) ) tan ( 2 ln ( x ) )}{x}

\int \frac{1}{2 x ^{3}} d x

x \frac{d y}{d x} = 2

\frac{91 t}{99 t - 91}

\frac{d}{d x} (2 x e^{2 x} + e^{2 x})

\int \frac{1}{1 - sin ( z )} d z

What is the derivative of sec(2ln(x)) ?
The derivative of sec(2ln(x)) is (2sec(2ln(x))tan(2ln(x)))/x
What is the first derivative of sec(2ln(x)) ?
The first derivative of sec(2ln(x)) is (2sec(2ln(x))tan(2ln(x)))/x