What is the integral from 1 to 2 of cos(x^2) ?

The integral from 1 to 2 of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)*2)-sqrt(pi/2)\C(sqrt(2/pi)*1)

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integral from 1 to 2 of cos(x^2)

\int_{1}^{2} cos (x^{2}) d x

\frac{π}{2} C (\frac{2}{π} \cdot 2) - \frac{π}{2} C (\frac{2}{π} \cdot 1)

Solution steps

\int_{1}^{2} cos (x^{2}) d x

Use the nonelementary integral:

\int cos (x^{2}) d x = \frac{π}{2} C (\frac{2}{π} x)

= [\frac{π}{2} C (\frac{2}{π} x)]_{1}^{2}

Compute the boundaries:

\frac{π}{2} C (\frac{2}{π} \cdot 2) - \frac{π}{2} C (\frac{2}{π} \cdot 1)

= \frac{π}{2} C (\frac{2}{π} \cdot 2) - \frac{π}{2} C (\frac{2}{π} \cdot 1)

\frac{\partial}{\partial y} (x^{2} + x y)

\frac{d}{d x} (\frac{9 x}{x})

\int \frac{2 - x}{x} d x

\frac{d}{d x} (cos^{2} (1 - x^{2}))

\frac{1 - 4 t}{3 + t}

What is the integral from 1 to 2 of cos(x^2) ?
The integral from 1 to 2 of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)*2)-sqrt(pi/2)\C(sqrt(2/pi)*1)