What is area y=3sqrt(x),y=(3x)/2 ?

The answer to area y=3sqrt(x),y=(3x)/2 is 4

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area y=3sqrt(x),y=(3x)/2

area

y = 3 x, y = \frac{3 x}{2}

4

Solution steps

Apply the area formula:

\int_{0}^{4} 3 x - \frac{3 x}{2} d x

Solve

\int_{0}^{4} 3 x - \frac{3 x}{2} d x : 4

The area is:

= 4

\frac{d}{d x} (- tan^{2} (x))

4 x - 3

\frac{\partial}{\partial x} (9 e^{x - y})

n = 2 \sum \infty \frac{4}{7 ^{n}}

f (x) = a^{5} + cos^{5} (x)