What is the tangent of f(x)=sin(x),\at x=(5pi)/2 ?

The tangent of f(x)=sin(x),\at x=(5pi)/2 is y=1

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tangent of f(x)=sin(x),\at x=(5pi)/2

tangent of

f (x) = sin (x), at x = \frac{5 π}{2}

y = 1

Solution steps

Find the tangent point:

(\frac{5 π}{2}, 1)

Find the slope of

f (x) = sin (x) : \frac{df ( x )}{d x} = cos (x)

Compute the slope of

f (x) = sin (x)

x = \frac{5 π}{2} : m = 0

Find the line with slope m=

0

and passing through

(\frac{5 π}{2}, 1) : y = 1

y = 1

\frac{1}{3 - x}

\int_{1}^{e} \frac{x ^{2} + x + 1}{x} d x

\int_{- 2}^{3} \frac{19}{x ^{4}} d x

x \to 2 lim (- \frac{1}{x - 2})

\int (3 - x^{2})^{3} d x

What is the tangent of f(x)=sin(x),\at x=(5pi)/2 ?
The tangent of f(x)=sin(x),\at x=(5pi)/2 is y=1