What is the derivative of ln(2x+1) ?

The derivative of ln(2x+1) is 2/(2x+1)

What is the first derivative of ln(2x+1) ?

The first derivative of ln(2x+1) is 2/(2x+1)

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derivative of

ln (2 x + 1)

\frac{2}{2 x + 1}

Solution steps

\frac{d}{d x} (ln (2 x + 1))

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= \frac{1}{2 x + 1} \cdot 2

Simplify

\frac{1}{2 x + 1} \cdot 2 : \frac{2}{2 x + 1}

= \frac{2}{2 x + 1}

x \to 5 lim (\frac{3}{x - 5})

\frac{d}{d x} (∣ x ∣^{x})

\int \frac{1}{x - x - 2} d x

\frac{d y}{d x} = \frac{( 3 x + 2 y )}{3 x + 2 y + 2}

\frac{\partial}{\partial x} (x^{4} + x \cdot sin (y))

What is the derivative of ln(2x+1) ?
The derivative of ln(2x+1) is 2/(2x+1)
What is the first derivative of ln(2x+1) ?
The first derivative of ln(2x+1) is 2/(2x+1)