What is the derivative of x+cos(x^2) ?

The derivative of x+cos(x^2) is 1-sin(x^2)*2x

What is the first derivative of x+cos(x^2) ?

The first derivative of x+cos(x^2) is 1-sin(x^2)*2x

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\frac{d}{d x} (x + cos (x^{2}))

1 - sin (x^{2}) \cdot 2 x

Solution steps

\frac{d}{d x} (x + cos (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (cos (x^{2}))

\frac{d x}{d x} = 1

\frac{d}{d x} (cos (x^{2})) = - sin (x^{2}) \cdot 2 x

= 1 - sin (x^{2}) \cdot 2 x

f (x) = x^{2} + x + 9, at x = 2

\int 5 e^{3 x} d x

h (w) = \frac{( x + 1 ) e ^{x}}{w - 2}

f (x) = 5 x^{2} - 5 x

\int \frac{2 x}{x - 4} d x

What is the derivative of x+cos(x^2) ?
The derivative of x+cos(x^2) is 1-sin(x^2)*2x
What is the first derivative of x+cos(x^2) ?
The first derivative of x+cos(x^2) is 1-sin(x^2)*2x