What is the extreme h(w)=((x+1)e^x)/(w-2) ?

The extreme h(w)=((x+1)e^x)/(w-2) is None

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extreme h(w)=((x+1)e^x)/(w-2)

extreme points

h (w) = \frac{( x + 1 ) e ^{x}}{w - 2}

None

Solution steps

Find the critical points:

None

\frac{( x + 1 ) e ^{x}}{w - 2}

has no critical points, therefore there are no extreme points

None

f (x) = 5 x^{2} - 5 x

\int \frac{2 x}{x - 4} d x

(x^{2} + 5) d x + (y - 3) (x - 2) d y = 0

\int 12 tan^{3} (x) d x

\int_{0}^{1} \frac{42}{4 y - 1} d y

What is the extreme h(w)=((x+1)e^x)/(w-2) ?
The extreme h(w)=((x+1)e^x)/(w-2) is None