What is (\partial)/(\partial x)(cos(2y-2x)) ?

The answer to (\partial)/(\partial x)(cos(2y-2x)) is 2sin(2y-2x)

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(\partial)/(\partial x)(cos(2y-2x))

\frac{\partial}{\partial x} (cos (2 y - 2 x))

2 sin (2 y - 2 x)

Solution steps

\frac{\partial}{\partial x} (cos (2 y - 2 x))

Treat

y

as a constant

Apply the chain rule:

- sin (2 y - 2 x) \frac{\partial}{\partial x} (2 y - 2 x)

= - sin (2 y - 2 x) \frac{\partial}{\partial x} (2 y - 2 x)

\frac{\partial}{\partial x} (2 y - 2 x) = - 2

= - sin (2 y - 2 x) (- 2)

Simplify

= 2 sin (2 y - 2 x)

\int (3 x^{2} - 2 x + 1) (x^{3} - x^{2} + x)^{4} d x

x \to 0 lim (\frac{1}{x} - \frac{1}{∣ x ∣})

x \to 3 lim (x^{2} + 7 x - 5)

\frac{d}{d x} (x^{2} cos (y))

\frac{d}{d x} ((x^{2} + 18) (2 x + 15))

What is (\partial)/(\partial x)(cos(2y-2x)) ?
The answer to (\partial)/(\partial x)(cos(2y-2x)) is 2sin(2y-2x)