What is the derivative of (x^5)/(5-x^4) ?

The derivative of (x^5)/(5-x^4) is (25x^4-x^8)/((5-x^4)^2)

What is the first derivative of (x^5)/(5-x^4) ?

The first derivative of (x^5)/(5-x^4) is (25x^4-x^8)/((5-x^4)^2)

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derivative of

\frac{x ^{5}}{5 - x ^{4}}

\frac{25 x ^{4} - x ^{8}}{( 5 - x ^{4} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{5}}{5 - x ^{4}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{5} ) ( 5 - x ^{4} ) - \frac{d}{d x} ( 5 - x ^{4} ) x ^{5}}{( 5 - x ^{4} ) ^{2}}

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (5 - x^{4}) = - 4 x^{3}

= \frac{5 x ^{4} ( 5 - x ^{4} ) - ( - 4 x ^{3} ) x ^{5}}{( 5 - x ^{4} ) ^{2}}

Simplify

\frac{5 x ^{4} ( 5 - x ^{4} ) - ( - 4 x ^{3} ) x ^{5}}{( 5 - x ^{4} ) ^{2}} : \frac{25 x ^{4} - x ^{8}}{( 5 - x ^{4} ) ^{2}}

= \frac{25 x ^{4} - x ^{8}}{( 5 - x ^{4} ) ^{2}}

\frac{d ^{3}}{d x ^{3}} (x^{3})

\frac{\partial}{\partial x} (x^{0.5} + y^{0.5})

f (x) = \frac{- 8 x}{x ^{2} + 1}, at x = - 1

\frac{d}{d x} (x (2 x - y^{3}))

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 10)^{6})

What is the derivative of (x^5)/(5-x^4) ?
The derivative of (x^5)/(5-x^4) is (25x^4-x^8)/((5-x^4)^2)
What is the first derivative of (x^5)/(5-x^4) ?
The first derivative of (x^5)/(5-x^4) is (25x^4-x^8)/((5-x^4)^2)