What is laplacetransform 0.03*(1-cos(2t)) ?

The answer to laplacetransform 0.03*(1-cos(2t)) is (0.12)/(s(s^2+4))

Popular >

laplacetransform 0.03*(1-cos(2t))

laplace transform

0.03 \cdot (1 - cos (2 t))

\frac{0.12}{s ( s ^{2} + 4 )}

Solution steps

L {0.03 (- cos (2 t) + 1)}

Expand

0.03 (1 - cos (2 t)) : 0.03 - 0.03 cos (2 t)

= L {0.03 - 0.03 cos (2 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {0.03} - 0.03 L {cos (2 t)}

L {0.03} : \frac{0.03}{s}

L {cos (2 t)} : \frac{s}{s ^{2} + 4}

= \frac{0.03}{s} - 0.03 \cdot \frac{s}{s ^{2} + 4}

Simplify

\frac{0.03}{s} - 0.03 \frac{s}{s ^{2} + 4} : \frac{0.12}{s ( s ^{2} + 4 )}

= \frac{0.12}{s ( s ^{2} + 4 )}

x \to 0 lim ((2 x^{2})^{x^{4}})

\frac{d}{d n} ((lo g_{10} (n))^{3})

\int \frac{1}{y ( 2 - y )} d y

f (x) = ln (\frac{1 - x}{1 + x})

\frac{\partial}{\partial x} ((x + x y + y)^{3})

What is laplacetransform 0.03*(1-cos(2t)) ?
The answer to laplacetransform 0.03*(1-cos(2t)) is (0.12)/(s(s^2+4))