What is area 5cos(4x),5-5cos(4x),[0, pi/4 ] ?

The answer to area 5cos(4x),5-5cos(4x),[0, pi/4 ] is (5pi+30sqrt(3))/(12)

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area 5cos(4x),5-5cos(4x),[0, pi/4 ]

area

5 cos (4 x), 5 - 5 cos (4 x), [0, \frac{π}{4}]

\frac{5 π + 30 3}{12}

Decimal Notation

5.63912 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{4}} ∣ 5 cos (4 x) - (5 - 5 cos (4 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{4}} ∣ 5 cos (4 x) - (5 - 5 cos (4 x)) ∣ d x : \frac{5 π + 30 3}{12}

The area is:

= \frac{5 π + 30 3}{12}

\frac{\partial}{\partial x} (2 x - 4 y^{2} + 3 z^{2})

x \to 0 - lim (\frac{- \frac{1}{2}}{4 x})

e^{(- x^{2})}

\int 5^{- x - 2} d x

\int 2 x e^{- x^{2}} d x

What is area 5cos(4x),5-5cos(4x),[0, pi/4 ] ?
The answer to area 5cos(4x),5-5cos(4x),[0, pi/4 ] is (5pi+30sqrt(3))/(12)