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Popular >

area y^2=x+1,x=3

Solution

area

y^{2} = x + 1, x = 3

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Isolate

y

for

y^{2} = x + 1 : y = x + 1, y = - x + 1

Apply the area formula:

\int_{- 1}^{3} 2 x + 1 d x

Solve

\int_{- 1}^{3} 2 x + 1 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

limit as x approaches 2-of (x-3)/(x+2)

x \to 2 - lim (\frac{x - 3}{x + 2})

integral of (4t^3)

\int (4 t^{3}) d t

derivative of f(x)= 1/x+1/(1-x)derivative of

f (x) = \frac{1}{x} + \frac{1}{1 - x}

integral of (x^3)/((5x+2)^3)

\int \frac{x ^{3}}{( 5 x + 2 ) ^{3}} d x

integral of (e^x)/(e^x+3)

\int \frac{e ^{x}}{e ^{x} + 3} d x

Frequently Asked Questions (FAQ)

What is area y^2=x+1,x=3 ?
The answer to area y^2=x+1,x=3 is 32/3