What is the d/(dθ)(sin(3θ)) ?

The d/(dθ)(sin(3θ)) is cos(3θ)*3

What is the first d/(dθ)(sin(3θ)) ?

The first d/(dθ)(sin(3θ)) is cos(3θ)*3

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\frac{d}{d θ} (sin (3 θ))

cos (3 θ) \cdot 3

Solution steps

\frac{d}{d θ} (sin (3 θ))

Apply the chain rule:

cos (3 θ) \frac{d}{d θ} (3 θ)

= cos (3 θ) \frac{d}{d θ} (3 θ)

\frac{d}{d θ} (3 θ) = 3

= cos (3 θ) \cdot 3

\int x^{2} a^{2 x} d x

\frac{d}{d x} (sech (x - 3) ln (x))

\int \frac{3}{x ( 1 + 3 x ) ^{2}} d x

\int \frac{x}{a ^{4} - x ^{4}} d x

y = 5 x - x^{2}