What is (\partial)/(\partial y)(x^3y^2) ?

The answer to (\partial)/(\partial y)(x^3y^2) is 2x^3y

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(\partial)/(\partial y)(x^3y^2)

\frac{\partial}{\partial y} (x^{3} y^{2})

2 x^{3} y

Solution steps

\frac{\partial}{\partial y} (x^{3} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{3} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{3} \cdot 2 y^{2 - 1}

Simplify

= 2 x^{3} y

\int cos (3 θ) d θ

x \to - 2 lim (\frac{3 x - 6}{x + 2})

\frac{d}{d x} (\frac{x ^{3}}{2 ( x + 1 ) ^{2}})

e^{x}

\int \frac{2 x ^{3} - 6 x ^{2} - 10 x - 6}{x ^{2} - 1} d x

What is (\partial)/(\partial y)(x^3y^2) ?
The answer to (\partial)/(\partial y)(x^3y^2) is 2x^3y