What is the derivative of 1-xe^x ?

The derivative of 1-xe^x is -e^xx-e^x

What is the first derivative of 1-xe^x ?

The first derivative of 1-xe^x is -e^xx-e^x

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\frac{d}{d x} (1 - x e^{x})

- e^{x} x - e^{x}

Solution steps

\frac{d}{d x} (1 - x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x e^{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

= 0 - (e^{x} + e^{x} x)

Simplify

= - e^{x} x - e^{x}

x^{2}, x + 2, y = 0

\frac{d}{d x} ((1 - x)^{3})

y = sec^{2} (x) - tan^{2} (x)

x \to \infty lim (A^{x})

8 - x e^{x}

What is the derivative of 1-xe^x ?
The derivative of 1-xe^x is -e^xx-e^x
What is the first derivative of 1-xe^x ?
The first derivative of 1-xe^x is -e^xx-e^x