What is the derivative of 8-xe^x ?

The derivative of 8-xe^x is -e^xx-e^x

What is the first derivative of 8-xe^x ?

The first derivative of 8-xe^x is -e^xx-e^x

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derivative of

8 - x e^{x}

- e^{x} x - e^{x}

Solution steps

\frac{d}{d x} (8 - x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) - \frac{d}{d x} (x e^{x})

\frac{d}{d x} (8) = 0

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

= 0 - (e^{x} + e^{x} x)

Simplify

= - e^{x} x - e^{x}

\frac{( s - 3 )}{s ^{2} - 4 s + 3}

4.8 t^{\frac{1}{3}}

\int_{0}^{1} x e^{9 x} d x

\frac{d}{d x} ((a^{\frac{2}{3}} - x^{\frac{2}{3}})^{\frac{3}{2}})

\frac{\partial}{\partial y} (e^{- 9 t} cos (π x))

What is the derivative of 8-xe^x ?
The derivative of 8-xe^x is -e^xx-e^x
What is the first derivative of 8-xe^x ?
The first derivative of 8-xe^x is -e^xx-e^x