What is the derivative of 2x^2-3x+1 ?

The derivative of 2x^2-3x+1 is 4x-3

What is the first derivative of 2x^2-3x+1 ?

The first derivative of 2x^2-3x+1 is 4x-3

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\frac{d}{d x} (2 x^{2} - 3 x + 1)

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 4 x - 3 + 0

Simplify

= 4 x - 3

- (x - 3)^{3}, 1

h \to 0 lim \frac{( ( 1 + h ) e ^{(1 + h)^{2}} - 3 )}{h}

f (x) = 5 x^{3}

\int - \frac{cos ( 3 x )}{3} d x

\int \frac{0.25}{( 0.2 5 ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of 2x^2-3x+1 ?
The derivative of 2x^2-3x+1 is 4x-3
What is the first derivative of 2x^2-3x+1 ?
The first derivative of 2x^2-3x+1 is 4x-3