What is the integral from 0 to pi of sin(4x) ?

The integral from 0 to pi of sin(4x) is 0

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integral from 0 to pi of sin(4x)

\int_{0}^{π} sin (4 x) d x

0

Solution steps

\int_{0}^{π} sin (4 x) d x

Apply u-substitution

: \int_{0}^{4 π} sin (u) \frac{1}{4} d u

= \int_{0}^{4 π} sin (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{4 π} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{4} [- cos (u)]_{0}^{4 π}

Compute the boundaries:

0

= \frac{1}{4} \cdot 0

Simplify

= 0

y = - 2 x^{2}, (- 5, 50)

y = \frac{1}{2} x^{2} + 1, (0, 1)

\int 2 x - 6 d x

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\int \frac{6}{15 sin ( x ) - 8 cos ( x )} d x

What is the integral from 0 to pi of sin(4x) ?
The integral from 0 to pi of sin(4x) is 0