What is the solution for y^{'''}+64y^'=0 ?

The solution for y^{'''}+64y^'=0 is y=c_{1}+c_{2}cos(8t)+c_{3}sin(8t)

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y^{'''}+64y^'=0

y^{^{'''}} + 64 y^{^{'}} = 0

y = c_{1} + c_{2} cos (8 t) + c_{3} sin (8 t)

Solution steps

y^{'''} (t) + 64 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} cos (8 t) + c_{3} sin (8 t)

y = c_{1} + c_{2} cos (8 t) + c_{3} sin (8 t)

f (x) = ln (100 sin^{2} (x))

\frac{d ^{2}}{d x ^{2}} (x^{\frac{8}{9}} + 6 x)

x \to - 1 lim (2 x + 4)

18 x

\int sin^{\frac{1}{2}} (2 x) cos^{3} (2 x) d x

What is the solution for y^{'''}+64y^'=0 ?
The solution for y^{'''}+64y^'=0 is y=c_{1}+c_{2}cos(8t)+c_{3}sin(8t)