What is the integral from 2 to infinity of 5x^{-2} ?

The integral from 2 to infinity of 5x^{-2} is 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of 5x^{-2}

\int_{2}^{\infty} 5 x^{- 2} d x

\frac{5}{2}

Decimal Notation

2.5

Solution steps

\int_{2}^{\infty} 5 x^{- 2} d x

Compute the indefinite integral:

\int 5 x^{- 2} d x = - \frac{5}{x} + C

Compute the boundaries:

\int_{2}^{\infty} 5 x^{- 2} d x = 0 - (- \frac{5}{2})

= 0 - (- \frac{5}{2})

Simplify

= \frac{5}{2}

\int x 5 + 2 x^{2} d x

a^{2} d x = x x^{2} - a^{2} d y

e^{2 t} sin (3 t)

y = 3 x, y = 9, y = \frac{1}{4} x^{2}

\int (x^{3} + 2)^{8} 3 x^{2} d x

What is the integral from 2 to infinity of 5x^{-2} ?
The integral from 2 to infinity of 5x^{-2} is 5/2