What is the integral of 1/(sqrt(2-x^2)) ?

The integral of 1/(sqrt(2-x^2)) is arcsin(1/(sqrt(2))x)+C

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integral of 1/(sqrt(2-x^2))

\int \frac{1}{2 - x ^{2}} d x

arcsin (\frac{1}{2} x) + C

Solution steps

\int \frac{1}{2 - x ^{2}} d x

Apply Trigonometric Substitution

: \int 1 d u

= \int 1 d u

Integral of a constant:

\int a d x = a x

= 1 \cdot u

Substitute back

u = arcsin (\frac{1}{2} x)

= 1 \cdot arcsin (\frac{1}{2} x)

Simplify

= arcsin (\frac{1}{2} x)

Add a constant to the solution

= arcsin (\frac{1}{2} x) + C

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\frac{d}{d x} (ln (5 x + 2))

x + 12

\frac{\partial}{\partial x} (- \frac{2 y}{3 + 2 x})

\int \frac{- 28}{x ^{2} x ^{2} + 25} d x

What is the integral of 1/(sqrt(2-x^2)) ?
The integral of 1/(sqrt(2-x^2)) is arcsin(1/(sqrt(2))x)+C