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Popular >

y^'-y=2te^2t

Solution

y^{^{'}} - y = 2 t e^{2} t

Solution

y = - 2 e^{2} (t^{2} + 2 (t + 1)) + c_{1} e^{t}

Solution steps

y^{'} (t) - y = 2 t e^{2} t

Solve linear ODE:

y = - 2 e^{2} (t^{2} + 2 (t + 1)) + c_{1} e^{t}

y = - 2 e^{2} (t^{2} + 2 (t + 1)) + c_{1} e^{t}

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Frequently Asked Questions (FAQ)

What is the solution for y^'-y=2te^2t ?
The solution for y^'-y=2te^2t is y=-2e^2(t^2+2(t+1))+c_{1}e^t