What is the derivative of ln(x-2x) ?

The derivative of ln(x-2x) is 1/x-2

What is the first derivative of ln(x-2x) ?

The first derivative of ln(x-2x) is 1/x-2

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\frac{d}{d x} (ln (x) - 2 x)

\frac{1}{x} - 2

Solution steps

\frac{d}{d x} (ln (x) - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) - \frac{d}{d x} (2 x)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (2 x) = 2

= \frac{1}{x} - 2

t sin (3 t) + 2 t cos (t)

f (x) = \frac{2 x + 1}{x + 2}, at x = 1

\frac{\partial}{\partial x} (- (5 x^{3} + 5 x y^{2}))

\frac{\partial}{\partial h} (x^{2} h)

\frac{1}{x + 2}

What is the derivative of ln(x-2x) ?
The derivative of ln(x-2x) is 1/x-2
What is the first derivative of ln(x-2x) ?
The first derivative of ln(x-2x) is 1/x-2