What is the solution for (x+2)(dy)/(dx)+y=ln(x),y(1)=20 ?

The solution for (x+2)(dy)/(dx)+y=ln(x),y(1)=20 is y=(xln(x))/(x+2)-x/(x+2)+(61)/(x+2)

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(x+2)(dy)/(dx)+y=ln(x),y(1)=20

(x + 2) \frac{d y}{d x} + y = ln (x), y (1) = 20

y = \frac{x ln ( x )}{x + 2} - \frac{x}{x + 2} + \frac{61}{x + 2}

Solution steps

(x + 2) \frac{d y}{d x} + y = ln (x)

Solve linear ODE:

y = \frac{x ln ( x )}{x + 2} - \frac{x}{x + 2} + \frac{61}{x + 2}

y = \frac{x ln ( x )}{x + 2} - \frac{x}{x + 2} + \frac{61}{x + 2}

x, x^{2}, 0, 1

\frac{\partial}{\partial y} (x^{2} y + y^{2} z)

\frac{d}{d x} (\frac{1}{x ( x + 1 )})

\int (3 t + 3)^{2.2} d t

y = 6 x - 11

What is the solution for (x+2)(dy)/(dx)+y=ln(x),y(1)=20 ?
The solution for (x+2)(dy)/(dx)+y=ln(x),y(1)=20 is y=(xln(x))/(x+2)-x/(x+2)+(61)/(x+2)