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Popular >

derivative of bx^2(x-4)

Solution

\frac{d}{d x} (b x^{2} (x - 4))

Solution

b (3 x^{2} - 8 x)

Solution steps

\frac{d}{d x} (b x^{2} (x - 4))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (x^{2} (x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = x - 4

= b (\frac{d}{d x} (x^{2}) (x - 4) + \frac{d}{d x} (x - 4) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 4) = 1

= b (2 x (x - 4) + 1 \cdot x^{2})

Simplify

b (2 x (x - 4) + 1 \cdot x^{2}) : b (3 x^{2} - 8 x)

= b (3 x^{2} - 8 x)

Popular Examples

derivative of (x^2/(x^2+3))

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + 3})

limit as x approaches 1 of 10x+1

x \to 1 lim (10 x + 1)

integral of x(x^2+2)^2

\int x (x^{2} + 2)^{2} d x

inverse oflaplace 4(((1))/(s^2+16))inverse laplace

4 (\frac{( 1 )}{s ^{2} + 16})

area y= 2/x ,y=7-x area

y = \frac{2}{x}, y = 7 - x

Frequently Asked Questions (FAQ)

What is the derivative of bx^2(x-4) ?
The derivative of bx^2(x-4) is b(3x^2-8x)
What is the first derivative of bx^2(x-4) ?
The first derivative of bx^2(x-4) is b(3x^2-8x)