What is the derivative of 3cos(x-4sin(x)) ?

The derivative of 3cos(x-4sin(x)) is -3sin(x)-4cos(x)

What is the first derivative of 3cos(x-4sin(x)) ?

The first derivative of 3cos(x-4sin(x)) is -3sin(x)-4cos(x)

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\frac{d}{d x} (3 cos (x) - 4 sin (x))

- 3 sin (x) - 4 cos (x)

Solution steps

\frac{d}{d x} (3 cos (x) - 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 cos (x)) - \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (3 cos (x)) = - 3 sin (x)

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= - 3 sin (x) - 4 cos (x)

\frac{e ^{x}}{7 x ^{2} + 5}

x \to 9 lim (x^{2})

\int cos (t) d t

\frac{e ^{- π s}}{s ^{2} + 9}

\int \frac{1}{( x ^{2} - 1 )} d x

What is the derivative of 3cos(x-4sin(x)) ?
The derivative of 3cos(x-4sin(x)) is -3sin(x)-4cos(x)
What is the first derivative of 3cos(x-4sin(x)) ?
The first derivative of 3cos(x-4sin(x)) is -3sin(x)-4cos(x)