What is the tangent of x^2+y^2=17,(4,-1) ?

The tangent of x^2+y^2=17,(4,-1) is y=4x-17

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tangent of x^2+y^2=17,(4,-1)

tangent of

x^{2} + y^{2} = 17, (4, - 1)

y = 4 x - 17

Solution steps

Find the slope of

x^{2} + y^{2} = 17 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 17

(4, - 1) : m = 4

Find the line with slope m=

4

and passing through

(4, - 1) : y = 4 x - 17

y = 4 x - 17

\int ln (6 x^{3}) d x

f (x) = x \cdot e^{x}

f (- 1) = (5 p + 4)^{40}

\int \frac{t}{1 - t} d t

What is the tangent of x^2+y^2=17,(4,-1) ?
The tangent of x^2+y^2=17,(4,-1) is y=4x-17