What is the integral of (1/(1+x^2)) ?

The integral of (1/(1+x^2)) is arctan(x)+C

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integral of (1/(1+x^2))

\int (\frac{1}{1 + x ^{2}}) d x

arctan (x) + C

Solution steps

\int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

x \to 0 lim ((1 + \frac{1}{x})^{x})

\frac{\partial}{\partial y} (x^{3} ln (y^{5}))

\frac{1}{( s + 4 ) ^{3}}

x^{2} \frac{d y}{d x} - 2 x y = 6 y^{4}

\frac{d y}{d x} = \frac{- y}{x}

What is the integral of (1/(1+x^2)) ?
The integral of (1/(1+x^2)) is arctan(x)+C