What is the limit as x approaches+(-1) of arccos(x) ?

The limit as x approaches+(-1) of arccos(x) is pi

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limit as x approaches+(-1) of arccos(x)

x \to + (- 1) lim (arccos (x))

π

Decimal Notation

3.14159 \dots

Solution steps

x \to - 1 lim (arccos (x))

Plug in the value

x = - 1

= arccos (- 1)

Use the following trivial identity:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π

f (x) = \frac{9}{5 + x ^{2}}, at x = 4

f (x) = x^{2} + 3, at x = 6

\int \frac{cosh ( x )}{x} d x

\frac{4 - 4 s}{4 s ^{2} + 4 s + 17}

f (x) = sec (x) + tan (x)

What is the limit as x approaches+(-1) of arccos(x) ?
The limit as x approaches+(-1) of arccos(x) is pi