What is the solution for (d^2y)/(dt^2)-9y=0 ?

The solution for (d^2y)/(dt^2)-9y=0 is y=c_{1}e^{3t}+c_{2}e^{-3t}

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(d^2y)/(dt^2)-9y=0

\frac{d ^{2} y}{d t ^{2}} - 9 y = 0

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

Solution steps

\frac{d ^{2} y}{d t ^{2}} - 9 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

\int (π^{3} - 1) d x

\frac{d}{d t} (2 t + 1)

\int 4 x^{2} + 9 d x

\frac{\partial}{\partial y} (ln (x + y))

f (x) = 6 x^{\frac{1}{5}} (x^{3} - 8)

What is the solution for (d^2y)/(dt^2)-9y=0 ?
The solution for (d^2y)/(dt^2)-9y=0 is y=c_{1}e^{3t}+c_{2}e^{-3t}