What is the derivative of f(v)=e^{2sin(3v)} ?

The derivative of f(v)=e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)

What is the first derivative of f(v)=e^{2sin(3v)} ?

The first derivative of f(v)=e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)

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derivative of

f (v) = e^{2 s i n (3 v)}

e^{2 s i n (3 v)} \cdot 6 cos (3 v)

Solution steps

\frac{d}{d v} (e^{2 s i n (3 v)})

Apply the chain rule:

e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

= e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

\frac{d}{d v} (2 sin (3 v)) = 6 cos (3 v)

= e^{2 s i n (3 v)} \cdot 6 cos (3 v)

\int sin (x) - cos (x) d x

n = 1 \sum \infty (- 3)^{n}

\frac{d y}{d x} = \frac{x - 3}{y + 5}

n = 1 \sum \infty 3 \cdot (\frac{1}{5})^{n}

n \to \infty lim (n^{2} e^{- 3 n})

What is the derivative of f(v)=e^{2sin(3v)} ?
The derivative of f(v)=e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)
What is the first derivative of f(v)=e^{2sin(3v)} ?
The first derivative of f(v)=e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)