What is the solution for -5/13 (dθ)/(dt)= 1/13 (5) ?

The solution for -5/13 (dθ)/(dt)= 1/13 (5) is θ(t)=-t+c_{1}

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-5/13 (dθ)/(dt)= 1/13 (5)

- \frac{5}{13} \frac{d θ}{d t} = \frac{1}{13} (5)

θ (t) = - t + c_{1}

Solution steps

- \frac{5}{13} \frac{d θ}{d t} = \frac{1}{13} (5)

Substitute

\frac{d θ}{d t}

with

θ^{'} (t)

- \frac{5}{13} θ^{^{'}} (t) = \frac{1}{13} (5)

Isolate

θ^{'} (t) : θ^{'} (t) = - 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

θ (t) = \int - 1 d t

\int - 1 d t = - t + c_{1}

θ (t) = - t + c_{1}

\int (\frac{2 x + 4}{x ^{2} + 4 x + 8}) d x

\int \frac{3}{2 - x - x ^{2}} d x

\int_{0}^{\frac{π}{4}} cos (6 x) d x

y^{^{'}} (e^{x} - 1) ln (y) = y

- \frac{16}{( 8 x + 9 ) ^{3}}

What is the solution for -5/13 (dθ)/(dt)= 1/13 (5) ?
The solution for -5/13 (dθ)/(dt)= 1/13 (5) is θ(t)=-t+c_{1}