What is the solution for (dy)/(dx)=(y^2+y)/(x^2+x) ?

The solution for (dy)/(dx)=(y^2+y)/(x^2+x) is y=(e^{c_{1}}x)/(x+1-e^{c_{1)}x}

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(dy)/(dx)=(y^2+y)/(x^2+x)

\frac{d y}{d x} = \frac{y ^{2} + y}{x ^{2} + x}

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + y}{x ^{2} + x}

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{x + 1 - e ^{c_{1}} x}

\int_{0}^{1} x e^{- 2 x} d x

y = 4 x^{2} - 1, y = 0, x = \frac{- 1}{2}, x = 1

\int \frac{x + 25}{x ^{2} + 24 x + 148} d x

y^{^{'}} = \frac{( cos ( 18 x ) )}{( e ^{(18 \cdot y)} )}

\int \frac{1}{2} e^{- \frac{1}{2} x} d x

What is the solution for (dy)/(dx)=(y^2+y)/(x^2+x) ?
The solution for (dy)/(dx)=(y^2+y)/(x^2+x) is y=(e^{c_{1}}x)/(x+1-e^{c_{1)}x}