What is laplacetransform-3sin(4t) ?

The answer to laplacetransform-3sin(4t) is -(12)/(s^2+16)

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laplacetransform-3sin(4t)

laplace transform

- 3 sin (4 t)

- \frac{12}{s ^{2} + 16}

Solution steps

L {- 3 sin (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 3 L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= - 3 \cdot \frac{4}{s ^{2} + 16}

Refine

- 3 \frac{4}{s ^{2} + 16} : - \frac{12}{s ^{2} + 16}

= - \frac{12}{s ^{2} + 16}

x \cdot \frac{d y}{d x} - x^{2} + x \cdot e^{- x} = 0

\frac{d}{d x} (\frac{x ^{5}}{5})

\frac{d}{d x} (\frac{6}{x + 1})

\frac{d}{d x} (cosh (x) - (2 e^{(- 0.3 x)}))

\frac{d P}{d t} = 0.1 P (1 - \frac{P}{830}) - \frac{1720}{83}

What is laplacetransform-3sin(4t) ?
The answer to laplacetransform-3sin(4t) is -(12)/(s^2+16)