What is the sum from n=0 to infinity of (2^n)/(n+1) ?

The sum from n=0 to infinity of (2^n)/(n+1) is diverges

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sum from n=0 to infinity of (2^n)/(n+1)

n = 0 \sum \infty \frac{2 ^{n}}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{2 ^{n}}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

\frac{s}{s ^{2} + 1}

- \frac{1}{( 2 x + 3 ) ^{\frac{3}{2}}}

\int 5 x^{3} (x - 5)^{- 4} d x

\frac{s + 2}{( s - 1 ) ( s + 6 )}

2 x, x^{2} - 4 x

What is the sum from n=0 to infinity of (2^n)/(n+1) ?
The sum from n=0 to infinity of (2^n)/(n+1) is diverges