What is the integral of 9x+5sin(x) ?

The integral of 9x+5sin(x) is (9x^2)/2-5cos(x)+C

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integral of 9x+5sin(x)

\int 9 x + 5 sin (x) d x

\frac{9 x ^{2}}{2} - 5 cos (x) + C

Solution steps

\int 9 x + 5 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x d x + \int 5 sin (x) d x

\int 9 x d x = \frac{9 x ^{2}}{2}

\int 5 sin (x) d x = - 5 cos (x)

= \frac{9 x ^{2}}{2} - 5 cos (x)

Add a constant to the solution

= \frac{9 x ^{2}}{2} - 5 cos (x) + C

\int x sin (8 x) d x

n = 1 \sum \infty 4 (- \frac{1}{7})^{4 n}

\int x sin (9 - x) d x

\frac{d}{d x} (2 arctan (\frac{1}{x}))

7 t

What is the integral of 9x+5sin(x) ?
The integral of 9x+5sin(x) is (9x^2)/2-5cos(x)+C