What is the derivative of ((-2x^2+2x)/((3x-3))) ?

The derivative of ((-2x^2+2x)/((3x-3))) is -2/3

What is the first derivative of ((-2x^2+2x)/((3x-3))) ?

The first derivative of ((-2x^2+2x)/((3x-3))) is -2/3

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\frac{d}{d x} (\frac{( - 2 x ^{2} + 2 x )}{( 3 x - 3 )})

- \frac{2}{3}

Solution steps

\frac{d}{d x} (\frac{( - 2 x ^{2} + 2 x )}{( 3 x - 3 )})

Simplify

\frac{( - 2 x ^{2} + 2 x )}{( 3 x - 3 )} : - \frac{2 x}{3}

= \frac{d}{d x} (- \frac{2 x}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{2}{3} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= - \frac{2}{3} \cdot 1

Simplify

= - \frac{2}{3}

\frac{d}{d x} (\frac{40}{3 x ^{\frac{1}{3}}})

x \to 0 lim (\frac{x + 4 - 2}{sin ( 5 x )})

\int 39 arctan (x) d x

\int 6 t sin (t) d t

y = 5 x - x^{2}, x

What is the derivative of ((-2x^2+2x)/((3x-3))) ?
The derivative of ((-2x^2+2x)/((3x-3))) is -2/3
What is the first derivative of ((-2x^2+2x)/((3x-3))) ?
The first derivative of ((-2x^2+2x)/((3x-3))) is -2/3