What is the derivative of 9log_{2}(x) ?

The derivative of 9log_{2}(x) is 9/(ln(2)x)

What is the first derivative of 9log_{2}(x) ?

The first derivative of 9log_{2}(x) is 9/(ln(2)x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (9 lo g_{2} (x))

\frac{9}{ln ( 2 ) x}

Solution steps

\frac{d}{d x} (9 lo g_{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (lo g_{2} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= 9 \cdot \frac{1}{x ln ( 2 )}

Simplify

9 \cdot \frac{1}{x ln ( 2 )} : \frac{9}{ln ( 2 ) x}

= \frac{9}{ln ( 2 ) x}

n \to \infty lim (e^{- n})

\frac{\partial}{\partial y} (2 x + 2 y)

e^{\frac{x}{( x - 4 )}}

y = \frac{5}{x}

What is the derivative of 9log_{2}(x) ?
The derivative of 9log_{2}(x) is 9/(ln(2)x)
What is the first derivative of 9log_{2}(x) ?
The first derivative of 9log_{2}(x) is 9/(ln(2)x)