What is the derivative of f(9)=3.6sqrt(x)+500 ?

The derivative of f(9)=3.6sqrt(x)+500 is (1.8)/(sqrt(x))

What is the first derivative of f(9)=3.6sqrt(x)+500 ?

The first derivative of f(9)=3.6sqrt(x)+500 is (1.8)/(sqrt(x))

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derivative of

f (9) = 3.6 x + 500

\frac{1.8}{x}

Solution steps

\frac{d}{d x} (3.6 x + 500)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3.6 x) + \frac{d}{d x} (500)

\frac{d}{d x} (3.6 x) = \frac{1.8}{x}

\frac{d}{d x} (500) = 0

= \frac{1.8}{x} + 0

Simplify

= \frac{1.8}{x}

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What is the derivative of f(9)=3.6sqrt(x)+500 ?
The derivative of f(9)=3.6sqrt(x)+500 is (1.8)/(sqrt(x))
What is the first derivative of f(9)=3.6sqrt(x)+500 ?
The first derivative of f(9)=3.6sqrt(x)+500 is (1.8)/(sqrt(x))