What is the limit as x approaches 1 of (5x-1)^{-2} ?

The limit as x approaches 1 of (5x-1)^{-2} is 1/16

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limit as x approaches 1 of (5x-1)^{-2}

x \to 1 lim ((5 x - 1)^{- 2})

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

x \to 1 lim ((5 x - 1)^{- 2})

Plug in the value

x = 1

= (5 \cdot 1 - 1)^{- 2}

Simplify

(5 \cdot 1 - 1)^{- 2} : \frac{1}{16}

= \frac{1}{16}

\frac{d}{d x} ((4 x - 4) (3 x^{3} - x^{2} + 1))

y = \frac{1}{16 x ^{2}}, y = x, y = \frac{x}{18}

f (x) = sin (cos (4 x))

\int 4 x cos (4 x) d x

\int (2^{x} - x^{2})^{2} d x

What is the limit as x approaches 1 of (5x-1)^{-2} ?
The limit as x approaches 1 of (5x-1)^{-2} is 1/16