What is the solution for sin(x)dx+ydy=0,y(0)=-2 ?

The solution for sin(x)dx+ydy=0,y(0)=-2 is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}

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sin(x)dx+ydy=0,y(0)=-2

sin (x) d x + y d y = 0, y (0) = - 2

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

Solution steps

sin (x) d x + y d y = 0

Solve separable ODE:

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

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\frac{d}{d x} (ln (arctan (x)))

\frac{d y}{d x} - 3 y = 0

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What is the solution for sin(x)dx+ydy=0,y(0)=-2 ?
The solution for sin(x)dx+ydy=0,y(0)=-2 is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}