What is the integral from 0 to 3 of pi(9x^2-x^4) ?

The integral from 0 to 3 of pi(9x^2-x^4) is pi 162/5

Popular >

integral from 0 to 3 of pi(9x^2-x^4)

\int_{0}^{3} π (9 x^{2} - x^{4}) d x

π \frac{162}{5}

Decimal Notation

101.78760 \dots

Solution steps

\int_{0}^{3} π (9 x^{2} - x^{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{3} 9 x^{2} - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{3} 9 x^{2} d x - \int_{0}^{3} x^{4} d x)

\int_{0}^{3} 9 x^{2} d x = 81

\int_{0}^{3} x^{4} d x = \frac{243}{5}

= π (81 - \frac{243}{5})

Join

81 - \frac{243}{5} : \frac{162}{5}

= π \frac{162}{5}

x \to 1 lim (e^{6 x^{5} - 6 x})

\int - \frac{17}{x ^{18}} d x

y = f (u) = u (y, x)^{3} - 4 y u (y, x) = g (x) = x^{3} + 3

f (x) = x^{2} - 2, at x = - 5, 23

x \to 3 π lim (e^{s i n (x)})

What is the integral from 0 to 3 of pi(9x^2-x^4) ?
The integral from 0 to 3 of pi(9x^2-x^4) is pi 162/5